KUNCI JAWABAN SOAL EKONOMI MIKRO NO 1

1. Diketahui

Q = 400 – 4P

MC = Rp. 20,-

v/Unit = Rp. 20,-

a. Jawaban A

Q = 400 – 4P

4P = 400 – Q

P = 100 – 0,25Q

TR = PxQ

TR = (100 – 0,25Q)xQ

TR = 100Q – 0,25Q²

^{MR = TR/Q} 

MR = 100 – 0,5Q

Πmax → MR =  MC

     100 – 0,5Q = 20

              0,5Q = 100 – 20

              0,5Q = 80

                       Q = 160 Unit

Masukkan ke persamaan

Q = 400 – 4P

160 = 400 – 4P

4P = 400 – 160

4P = 240

P  = 60

Maka πmax = TR – TC

                         (P.Q) – (v.Q)

                        (60x160) – (20x160)

         Πmax =  9600 – 3200 = Rp. 6400

b. Jawaban B

TR max → MR = 0  ( Syarat )

MR = 0

100 – 0,5Q = 0

          0,5Q = 100

Q = 100/0,5 = 200 Unit

TR = P.Q

     = (100 – 0,25Q).Q

     = (100 – 0,25(200)).200

     = (100 – 50).200

TR = Rp. 1000000

Q = 400 – 4P

200 = 400 – 4P

4P = 400 – 200

4P = 200

P   = 200/4, P = Rp. 50,-

Maka πmax = TR – TC

                         (P.Q) – (v.Q)

                        (50x200) – (20x200)

         Πmax =  10000 – 4000 = Rp. 6000,-